Array in ascending order in C
Problem statement
Given an array, sort in ascending order.
Solution
Use two for loops, Outer for loop for preserving index and the element at that index and inner one to iterate over remaining array.
for (i = 0; i < n; ++i){
  for (j = i + 1; j < n; ++j){
   if (num[i] > num[j]){
     a = num[i];
     num[i] = num[j];
     num[j] = a;
   }
  }
}
[code language=”cpp”]
#include <stdio.h>
int main()
{
int num[20];
int i, j, a, n;
printf("Enter array limit:\n");
scanf("%d", &n);
if (n > 20)
{
printf("Array limit out of range!");
return 0;
}
printf("Enter array elements:\n");
for (i = 0; i < n; ++i)
scanf("%d", &num[i]);
for (i = 0; i < n; ++i)
{
for (j = i + 1; j < n; ++j)
{
if (num[i] > num[j])
{
a = num[i];
num[i] = num[j];
num[j] = a;
}
}
}
printf("Array sorted in ascending order:\n");
for (i = 0; i < n; ++i)
{
printf("%d\t", num[i]);
}
return 0;
}
[/code]
| $ ./a.out Enter array limit: 7 Enter array elements: 8 7 6 5 4 3 2 Array sorted in ascending order: 2 3 4 5 6 7 8 $ ./a.out Enter array limit: 2 Enter array elements: 3 4 Array sorted in ascending order: 3 4 $ ./a.out Enter array limit: 2 Enter array elements: 1 1 Array sorted in ascending order: 1 1 $ ./a.out Enter array limit: 34 Array limit out of range! $ |
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